Solving the Homogeneous Differential Equation dy/dx = (y - x)/(y + x) - Продолжительность: 12:13 The Math Sorcerer 59 913 просмотров. The solution of the differential equ `(x^2 + y^2) dx = 2 xy dy` is- - Продолжительность: 2:46 Doubtnut 12 865 просмотров Решение интегралов ∫dx Currently Hino is on DX2 version 150, which is what you will receive in need to find d^2y /dx^2 of an equation but i dont know how to do it. 1 decade ago. The derivative of a function at a point is the slope of the line tangent to the original curve at that point. d^2y/dx^2 is the second derivative, so just take the derivative of dy/dx to ge dx*(x^2 - y^2) - 2*dy*x*y = 0

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Share this Rating. Title: Pia Carrot e Yokoso! 2 DX (1999- ) d2y/dx2 = d/dy [1/2 (y'^2)] so how do we show that the LHS = RHS? starting from the LHS? i don't really understand. my lecturer made it become... D2y / dx2. Thread starter quietrain

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- Найти dy/dx (d^2y)/(dx^2)=4x^3+3x^2
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